#include <stdio.h> #include <stdint.h> // Complete the function // 8 = 1000 16 0000 1000 const char* is_power_of_two(uint32_t n) { // Your logic here take note if(n>0&&(n &(n-1))==0){ return "YES"; }else{ return "NO"; } } int main() { uint32_t n; scanf("%u", &n); const char* result = is_power_of_two(n); printf("%s", result); return 0; }
Test Cases
Test Results
Input
8
Expected Output
YES