Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
// Don't use loops (for, while, do-while), multiplicatinon(*), division (/), lib (cmath / math.h)
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    if(n>0){
        if((n&(n-1)) == 0 ){
            return "YES\n";
        }else return "NO\n";
    }
    return "NO\n";
    
}


int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach