Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>


// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    if (n == 0) return "NO";
    uint32_t result = 0x00;
    //since comparison between (e.g. 1000 and 0111 this will result to true)
    result = n & (n - 1);
    if (result == 0)
    {
        return "YES";
    } 
    else
    {
        return "NO";
    }

    
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach