Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    if((n&(n-1))==0 && n>0)
    return "YES";
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

const char* is_power_of_two(uint32_t n) {

    // Your logic here

    if((n&(n-1))==0 && n>0)    

    return "YES";

    return "NO";

}

Step :- 1 checking the n is greater than 0 and n & n-1 is equal to zero .

Step :- 2 return "YES"

    if((n&(n-1))==0 && n>0)    

    return "YES";

    return "NO";