Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    uint32_t tmp = 0;
    if(n==0){
        return "NO";
    }
    for (int i = 0;i<32;i++){
        if (((n >> i) & (1U)) == 1){
            tmp++ ;
        }
        if(tmp > 1){
            return "NO";
        }
    }
    // Your logic here
    return "YES";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach