Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>
const char* is_power_of_two(uint32_t n) 
{
    // Your logic here
    if( (n>0) && ((n & (n-1))==0))
    {
        return "YES";
    }
    return "NO";
}
int main() 
{
    uint32_t n;
    scanf("%u", &n);
    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach