Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // 1000 1000 -> 1000 0111 (doesn't work)
    // 1000 0000 -> 0111 1111 (does)
    // 0001 0000 -> 0000 1111 (does)
    // edge case of 0:
    if (n == 0) return "NO";
    if ((n & (n - 1)) == 0) return "YES";
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

8

Expected Output

YES