Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    int c=0;
    while(n){
        if(n&1){
            c+=1;
        }
        n>>=1;
    }
    if(c==1){
        return "YES";
    }
    else{
        return "NO";
    }
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

simple looping and bitwise logic concepts