Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // power of 2 is only possible when only 1 bit set
    // if (n == 0) return "NO";
    // uint8_t count = 0; // count of set bits
    // while (n)
    // {
    //     count += (n & 1); 
    //     if (count > 1) return "NO";
    //     n >>= 1; 
    // }

    // return "YES";

    if ((n != 0) && ((n & (n - 1)) == 0))
    {
        return "YES";
    }
    else
    {
        return "NO";
    }
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach