Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    // if (n == 1) return "YES";
    // if (n == 0) return "NO";
    // if ((n > 1) && (n & 1))
    // {
    //     return "NO";
    // } 
    // return "YES";
    if ((n > 0) && (n & (n - 1)) == 0)
    {
        return "YES";
    }
    else return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach