Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

const char* is_power_of_two(uint32_t n) {
   if(n==0)  return "NO" ; 
   else{
    n=(n-1) & n;
    if(n==0) return "YES" ; 
    else return "NO" ; 
   }
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

 

 

 

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Input

8

Expected Output

YES