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Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // A power of 2 means that only 1 bit is set
    uint32_t var = n & (n - 1U);
    // The second case checks for 0 and negative values
    if (var == 0 && n > 0) {
        return "YES";
    } else {
        return "NO";
    }
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach

 

 

 

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Input

8

Expected Output

YES