Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    int cnt=0,i;
    for(i=31;i>=0;i--)
    {
        if((n>>i)&1)
        cnt++;

    }
    if(cnt==1)
    return "YES";
    // Your logic here
    return "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach