Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    int counter = 0;
    for (int index = 0; index < 32; index++) {
        if ((n >> index) & 1) {
            counter++;
        }
    }

    if (counter == 1) {
        return "YES";
    } else {
        return "NO";
    }
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach