Check If a Number Is a Power of Two

Code

#include <stdio.h>
#include <stdint.h>

// Complete the function
const char* is_power_of_two(uint32_t n) {
    // Your logic here
    uint8_t count = 0;
    for (size_t i = 0; i < sizeof(n) * 8; i++) {
        if (n & (1 << i)) count++;
    }

    return (count == 1) ? "YES" : "NO";
}

int main() {
    uint32_t n;
    scanf("%u", &n);

    const char* result = is_power_of_two(n);
    printf("%s", result);
    return 0;
}

Solving Approach