#include <stdio.h> #include <stdint.h> uint16_t binary_to_uint(const char *str) { // Your logic here uint16_t int_value=0; for(int i=0;str[i]!='\0';i++){ int_value=int_value*2+(str[i]-'0'); } return int_value; } int main() { char bin[20]; scanf("%s", bin); printf("%u", binary_to_uint(bin)); return 0; }
Test Cases
Test Results
Input
1010
Expected Output
10