#include <stdint.h> #include <stdio.h> uint16_t binary_to_uint(const char *str) { // Your logic here uint16_t num; int i = 0; while (str[i] != '\0') { num = num * 2 + (str[i] - '0'); i++; } return num; } int main() { char bin[20]; scanf("%s", bin); printf("%u", binary_to_uint(bin)); return 0; }
Test Cases
Test Results
Input
1010
Expected Output
10