#include <stdio.h> #include <stdint.h> uint16_t binary_to_uint(const char *str) { // Your logic here uint8_t i=0; uint16_t num=0; while(*(str+i)!='\0'){ num=(num<<1|(*(str+i)-'0')); i++; } return num; } int main() { char bin[20]; scanf("%s", bin); printf("%u", binary_to_uint(bin)); return 0; }
Test Cases
Test Results
Input
1010
Expected Output
10