#include <stdio.h> #include <stdint.h> #include <math.h> #include<string.h> uint16_t binary_to_uint(const char *str) { // Your logic here int n = strlen(str); int num = 0; int j = 0; for(int i=n-1;i>=0;i--){ num += (pow(2,j)*(str[i]-'0')); j++; } return num; } int main() { char bin[20]; scanf("%s", bin); printf("%u", binary_to_uint(bin)); return 0; }
Test Cases
Test Results
Input
1010
Expected Output
10