#include <stdio.h> #include <stdint.h> #include <string.h> #include <math.h> uint16_t binary_to_uint(const char *str) { // Your logic here int l = strlen(str); uint16_t num = 0; for(int x=l-1;x>=0;x--) { num += (str[x] - '0')*(int)pow(2,l-1-x); } return num; } int main() { char bin[20]; scanf("%s", bin); printf("%u", binary_to_uint(bin)); return 0; }
Test Cases
Test Results
Input
1010
Expected Output
10