Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    uint16_t result =0;
    while(*str!='\0')
    {        
        result <<= 4;
        result |= ((*str>='0')&&(*str<'9'))?*str-'0':
                  ((*str>='a')&&(*str<'f'))?*str-'a'+10:*str-'A'+10;
        // printf("*str=%c result=%d \n",*str,result);
        str++;
    }
    return result;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}