Convert Hexadecimal String to Integer Without strtol or sscanf functions

Code

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    uint16_t number = 0;
    for(int i=0; str[i]; i++)
    {
        if(str[i]>='0' && str[i]<='9')
            number = (number << 4) | (str[i] - '0');
        else if(str[i]>='A' && str[i]<='F')
            number = (number << 4) | (str[i] - 'A' + 10);
        else if(str[i]>='a' && str[i]<='f')
            number = (number << 4) | (str[i] - 'a' + 10);
    }
    return number;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}

Solving Approach