119. Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    uint16_t result = 0;
    for(int i = 0; str[i] != 0; i++){
        char c = str[i];
        uint8_t value= 0;

        if(c >= '0' && c <= '9'){
            value = c - '0';
        }
        else if(c >= 'A' && c <= 'F' ){
            value = (c - 'A') + 10;
        }
        else if(c >= 'a' && c <= 'f' ){
            value = (c - 'a') + 10;
        }
        result = (result << 4) | value;
    }

    return result;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}