#include <stdio.h> #include <stdint.h> uint16_t hex_to_uint(const char *str) { // Your logic here uint16_t ans = 0; while(*str != '\0'){ char x = *str; int digit = 0; if(x >= 'a'){ digit = x - 'a' + 10; }else if(x >= 'A'){ digit = x-'A' +10; }else{ digit = x -'0'; } ans = (ans<<4)|digit; str++; } return ans; } int main() { char hex[10]; scanf("%s", hex); printf("%u", hex_to_uint(hex)); return 0; }
Test Cases
Test Results
Input
1A3F
Expected Output
6719