119. Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    uint16_t val=0;
    for(int i=0;str[i];i++){
        char c=str[i];
        int digit;
        if( c>='0'&&c<='9'){
            digit = c-'0';
        }else if( c>='A'&&c<='F'){
            digit = c-'A'+10;
        }else if(c >= 'a' && c <= 'f' ){
            digit= c-'a'+10;
        }else{
            continue;
        }
        val=(val<<4)|uint16_t(digit);
    }
    return val;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}