Convert Hexadecimal String to Integer Without strtol or sscanf functions

Code

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str)
{
    uint16_t val = 0;
    uint16_t digit = 0;

    for (int i = 0; str[i]; i++)
    {
        char c = str[i];

        if (c >= '0' && c <= '9')
            digit = c - '0';
        else if (c >= 'A' && c <= 'F')
            digit = c - 'A' + 10;
        else if (c >= 'a' && c <= 'f')
            digit = c - 'a' + 10;

        val = (val << 4 ) | digit;
    }

    return val;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}

Solving Approach