119. Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    uint16_t val = 0;
    while(*str != 0){
        if(*str>= '0' && *str <='9'){
            val = val*16 + (*str - '0');
        }else if( (*str >= 'A' && *str <='F'))
            val = val*16 + (*str - 'A'+10);
        else if ((*str >= 'a' && *str <= 'f') )
            val = val*16 + (*str - 'a' + 10);
    
    str++;
    }
    return val;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}