119. Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    uint16_t result = 0;
    while(*str) {
        uint16_t digit;
        if(*str >='0' && *str <= '9') {
            digit = *str - '0';
        } else if(*str >='A' && *str <= 'F') {
            digit = *str - 'A' + 10;
        } else if (*str >='a' && *str <= 'f') {
            digit =  *str - 'a' + 10;
        } else {
            str++;
            continue;
        }

        result = result * 16 + digit;
        str++;
    }
    return  result;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}