119. Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    uint16_t result = 0;
    while (*str){
        if (*str >= '0' && *str <= '9'){
            result = result * 16 + (*str - '0');
        } else if (*str >= 'A' && *str <= 'F'){
            result = result * 16 + (*str - 'A' + 10);
        } else if (*str >= 'a' && *str <= 'f'){
            result = result * 16 + (*str - 'a' + 10);
        }
        str++;
    }
    return result;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}