Convert Hexadecimal String to Integer Without strtol or sscanf functions

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    int val = 0;
    int i = 0;
    while(str[i] != '\0'){
        char c = str[i];
        if (c >= 'a' && c <= 'z'){
            c = c - 32;
        }
        int digit = (c >= 'A') ? (c - 'A' + 10) : (c -'0');
        val = (val << 4) | digit;
        i++;
    }
    return val;
}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}