Convert Hexadecimal String to Integer Without strtol or sscanf functions

Code

#include <stdio.h>
#include <stdint.h>

uint16_t hex_to_uint(const char *str) {
    // Your logic here
    int kq=0;

   while (*str!='\0'){
        if (*str>='0'&&*str<='9'){
        kq=kq<<4|(*str-'0');
        str++;
        }
        else if (*str<='F'&&*str>='A') {
        kq=kq<<4|(*str-55);
        str++;
        }
        else {
        kq=kq<<4|(*str-87);
        str++;
        }
   }
   return kq;

}

int main() {
    char hex[10];
    scanf("%s", hex);

    printf("%u", hex_to_uint(hex));
    return 0;
}

Solving Approach