Extract Bit Field from 16-bit Register

Code

#include <stdio.h>
#include <stdint.h>

uint8_t extract_field(uint16_t reg) {
    // Your logic here
    int mask = (1u << 5 ) - 1;
    uint8_t result =  (reg >> 4) & mask;
    return result;
    // Binary = 0000 0001 1111 0000 → bits 4–8 are all 1)
}

int main() {
    uint16_t reg;
    scanf("%hx", &reg);
    printf("%u", extract_field(reg));
    return 0;
}

Solving Approach