We have already declared a namespace MathOps with:
- A variable
int x = 10; - A function
int square(int n) that returns n * n
Your task is to:
- Print the value of
x - Call
square(x) and print the result
Example Output:
x=10 Square=100
Why this output?
Because the variable x is accessed using MathOps::x, and the function is called using MathOps::square(10).
Question Significance
Demonstrates how to access variables and functions defined inside a namespace using the scope resolution operator.