Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char time[7]={0};
    float latt=0.0f,lon=0.0f;
    char flatt,flon;
    char printime[9]={0};
    sscanf(nmea,"$GPRMC,%6[^,],A,%f,%c,%f,%c",time,&latt,&flatt,&lon,&flon);
    snprintf(printime,sizeof(printime),"%c%c:%c%c:%c%c",time[0],time[1],time[2],time[3],time[4],time[5]);
    printf("Time: %s\n",printime);
    printf("Latitude: %08.3f %c\n",latt,flatt);
    printf("Longitude: %09.3f %c\n",lon,flon);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E