Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char *fields[7];
    int index=0;
    char *token=strtok(nmea,",");
    while(token!=NULL&&index<7){
        fields[index++]=token;
        token=strtok(NULL,",");
    }
    //extracting time
    char *t=fields[1];
    printf("Time: %.2s:%.2s:%.2s\n", t, t+2, t+4);
    //latitude
    printf("Latitude: %s %s\n",fields[3],fields[4]);
    //longitude
    printf("Longitude: %s %s\n",fields[5],fields[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E