Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void split_string(const char *str, char tokens[6][13]) {
    int i = 0, j = 0;
    while(*str != '\0'){
        if(*str == ','){
            tokens[i][j] = '\0';
            i++;
            j = 0;
        }else
            tokens[i][j++] = *str;
        str++;
    }
    tokens[i][j] = '\0';
}

void parse_gprmc(char *nmea) {
    char tokens[6][13];
    nmea+=7;
    split_string(nmea, tokens);
    char *time_str = tokens[0];
    printf("Time: %.2s:%.2s:%.2s\n", time_str, time_str + 2, time_str + 4);
    printf("Latitude: %s %s\n", tokens[2], tokens[3]);
    printf("Longitude: %s %s", tokens[4], tokens[5]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E