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Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    char *fields[7];
    int index = 0;
    char *token = strtok(nmea, ",");
    while (token && index < 7) {
        fields[index++] = token;
        token = strtok(NULL, ",");
    }

    // Extract time
    char *t = fields[1];
    printf("Time: %.2s:%.2s:%.2s\n", t, t+2, t+4);

    // Extract latitude
    printf("Latitude: %s %s\n", fields[3], fields[4]);

    // Extract longitude
    printf("Longitude: %s %s", fields[5], fields[6]);

    /* manual parsing
    char *subfield = &nmea[7];
    char c;
    int idx = 1;
    printf("Time: ");
    while (c = *subfield++) {
        if (c == ',')
            break;
        printf("%c", c);
        if (idx == 2 || idx == 4)
            printf(":");
        idx++;
    }

    while (*subfield++ != ',')

    printf("\nLatitude: ");
    while (c = *subfield++) {
        if (c == ',')
            break;
        printf("%c", c);
    }
    printf(" %c", *subfield++);

    subfield++;
    printf("\nLongitude: ");
    while (c = *subfield++) {
        if (c == ',')
            break;
        printf("%c", c);
    }
    printf(" %c\n", *subfield++);
    */
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E