Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    int time=0;
    char lat[9];
    strcpy(lat,"");
    char lon[10];
    strcpy(lon,"");
    char d1,d2,T;
    int t=0;
    for (int i=0;nmea[i]!='\0';i++)
    {
            
        if(nmea[i]==',') t++;
        else if(t==1) time=time*10+nmea[i]-48;
        else if(t==3) strncat(lat,&nmea[i],1);
        else if(t==4) d1=nmea[i];
        else if(t==5) strncat(lon,&nmea[i],1);
        else if(t==6) d2=nmea[i];
        
    }
    int h=time/10000;
    int m=time/100-h*100;
    int s=time%100;
    printf("Time: %02d:%02d:%02d\n",h,m,s);
    printf("Latitude: %s %c\n",lat,d1);
    printf("Longitude: %s %c\n",lon,d2);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E