Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char fields[6][10];
    int string_idx = -1;
    int string_count = -1;
    int delimiter_flag = 0;

    while(*nmea != '\0'){
        if(*nmea == ','){
            delimiter_flag = 1;
        }
        else if(string_count!=-1 && string_count<=5){
            fields[string_count][string_idx++] = *nmea;
        }

        if(delimiter_flag){
            if(string_count != -1){
                fields[string_count][string_idx] = '\0';
            }
            string_idx = 0;
            string_count++;
            delimiter_flag = 0;
        }

        nmea++;
    }

    fields[string_count][string_idx] = '\0';

    printf("Time: %.2s:%.2s:%.2s\n", &fields[0][0], &fields[0][2], &fields[0][4]);
    printf("Latitude: %s %s\n", fields[2], fields[3]);
    printf("Longitude: %s %s\n", fields[4], fields[5]);

    return;
    
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E