Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char tokens[7][20];
    int count = 0;
    int idx = 0;

    for(int i=0; nmea[i] != '\0'; i++)
    {
        char ch = nmea[i];

        if(ch == ',')
        {
            if(idx > 0)
            {
                tokens[count][idx] = '\0';
                count++;
                idx = 0;
            }
        }
        else
        {
            tokens[count][idx++] = ch;
        }
    }
    if(idx > 0)
    {
        tokens[count][idx] = '\0';
        count++;
    }

    printf("Time: %c%c:%c%c:%c%c\n", tokens[1][0], tokens[1][1], tokens[1][2], tokens[1][3], tokens[1][4], tokens[1][5]);
    printf("Latitude: %s %s\n", tokens[3], tokens[4]);
    printf("Longitude: %s %s", tokens[5], tokens[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E