Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char data[7][10];
 

    int x =0;
    int y =0;
    while(!(*nmea=='\0')){
            if (!(*nmea==',')){
               data[x][y] = *nmea;
               y++;
            }
            else { //delimiter
                data[x][y] == '\0';
                x++;
                y=0;
            } 
    nmea++;
    }
    //last delimiter
    data[x][y] = '\0';

printf("Time: %.2s:%.2s:%.2s\n",(char*)(data[1]),(char*)(data[1]+2),(char*)(data[1]+4));
printf("Latitude: %s %.1s\n",data[3],data[4]);
printf("Longitude: %s %.1s\n",data[5],data[6]);



}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach