Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>
#include <stdint.h>

void parse_gprmc(char *nmea) {
    // Your logic here
     char fields[7][20];
    uint8_t row = 0, col = 0, i = 0;

    while(nmea[i] != '\0' && row < 7)
    {
        if(nmea[i] == ',')
        {
            fields[row][col] = '\0';
            row++;
            col = 0;
        }
        else
        {
            fields[row][col++] = nmea[i];
        }
        i++;
    }

    fields[row][col] = '\0';

    /* Extract time */
    char *time = fields[1];

    printf("Time: %c%c:%c%c:%c%c\n",
           time[0], time[1],
           time[2], time[3],
           time[4], time[5]);

    printf("Latitude: %s %s\n", fields[3], fields[4]);
    printf("Longitude: %s %s\n", fields[5], fields[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E