Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void process_time(const char *time, char *actual_time) {
    char hh[3], mm[3], ss[3];

    strncpy(hh, time, 2);
    hh[2] = '\0';
    strncpy(mm, time + 2, 2);
    mm[2] = '\0';
    strncpy(ss, time + 4, 2);
    ss[2] = '\0';

    snprintf(actual_time, 15, "%s:%s:%s", hh, mm, ss);
}

void parse_gprmc(char *nmea) {
    char format[10], time[15], lat[15], longit[15], status[15], ns[15], ew[15];

    if (sscanf(nmea, "%[^,],%[^,],%[^,],%[^,],%[^,],%[^,],%[^,]", 
               format, time, status, lat, ns, longit, ew) != 7) {
        printf("Failed to parse NMEA string.\n");
        return;
    }

    char actual_time[15];
    process_time(time, actual_time);

    printf("Time: %s\n", actual_time);
    printf("Latitude: %s %s\n", lat, ns);
    printf("Longitude: %s %s\n", longit, ew);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    nmea[strcspn(nmea, "\n")] = '\0'; // Remove newline

    parse_gprmc(nmea);
    return 0;
}

Solving Approach