Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char fields[6][20];
    int field_num = 0;
    int char_idx = 0;
    
    char *ptr = nmea;
    
    while (*ptr != ',' && *ptr != '\0') ptr++;
    if (*ptr == ',') ptr++;
    
    while (*ptr != '\0' && field_num < 6) {
        if (*ptr == ',') {
            fields[field_num][char_idx] = '\0';  
            field_num++;
            char_idx = 0;
        } else {
            fields[field_num][char_idx++] = *ptr;
        }
        ptr++;
    }
    
    if (char_idx > 0) {
        fields[field_num][char_idx] = '\0';
    }
    
    printf("Time: %.2s:%.2s:%.2s\n", fields[0], fields[0]+2, fields[0]+4);
    printf("Latitude: %s %s\n", fields[2], fields[3]);
    printf("Longitude: %s %s\n", fields[4], fields[5]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach