Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    printf("Time: %c%c:%c%c:%c%c\n",nmea[7],nmea[8],nmea[9],nmea[10],nmea[11],nmea[12]);
    printf("Latitude: ");
    for(int i=16;i<25;i++){
        if(nmea[i]!= ','){
        printf("%c",nmea[i]);
        }
    }
    printf(" %c\n",nmea[25]);  
    
    printf("Longitude: ");
    for(int i=27;i<37;i++){
        if(nmea[i]!=','){
            printf("%c",nmea[i]);
        }
    }
    printf(" %c\n",nmea[37]);  
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E