Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    int i = 0;
    int j =0;
    char tokens[10][20];
    while (*nmea) {
        if (*nmea == ',') {
            tokens[i][j] = '\0';
            i++;
            j = 0;
        } 
        else {
            tokens[i][j] = *nmea;
            j++;
        }
        nmea++;
    }

    char time[9];
    time[0] = tokens[1][0];
    time[1] = tokens[1][1];
    time[2] = ':';

    time[3] = tokens[1][2];
    time[4] = tokens[1][3];
    time[5] = ':';

    time[6] = tokens[1][4];
    time[7] = tokens[1][5];
    time[8] = '\0';

    tokens[i][j] = '\0';
    printf("Time: %s\n",time);
    printf("Latitude: %s %s\n",tokens[3],tokens[4]);
    printf("Longitude: %s %s\n",tokens[5],tokens[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E