Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    char time[100],lat[100],lon[100];
    int index=0;
    for(int i=7;i<13;i++){
        if(i%2!=0 && i!=7){
            time[index]=':';
            index+=1;
        }
        time[index]=*(nmea+i);
        index+=1;
    }
    time[index]='\0';
    printf("Time: %s\n",time);
    int y=0;
    for(int i=16;i<24;i++){
        lat[y]=*(nmea+i);
        y+=1;
    }
    lat[y]='\0';
    printf("Latitude: %s %c\n",lat,*(nmea+25));
    int x=0;
    for(int i=27;i<36;i++){
        lon[x]=*(nmea+i);
        x+=1;
    }
    lat[x]='\0';
    printf("Longitude: %s %c",lon,*(nmea+37));

}


int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

simple string pointer helped me to solve the problem