Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    nmea = nmea + 7;
    int count = 0; 
    char time[16]; 
    char lat[16]; 
    char longitude[16]; 

    for (int i = 0; i < 8; i++){ 
        if (count == 2){ 
            time[i] = ':'; 
            count = 0;
        } else { 
            time[i] = *nmea; 
            nmea++; 
            count++; 
        }
    }
    time[9] = '\0'; 
    nmea = nmea + 3; 

    for (int i = 0; i < 10; i++){ 
        // printf("%c \n", *nmea);
        if (*nmea == ','){ 
            lat[i] = ' '; 
        } else { 
            lat[i] = *nmea; 
            // printf("here at %d %c \n", i, lang[i]);
        }
        nmea++; 
    }
    lat[10] = '\0';
    nmea++; 
    for (int i = 0; i < 11; i++){ 
        if (*nmea == ','){ 
            longitude[i] = ' '; 
        } else { 
            longitude[i] = *nmea; 
        }
        nmea++; 
    }
    
    // longitude[0] = *nmea; 
    longitude[11] = '\0'; 

    printf("Time: %s\n", time); 
    printf("Latitude: %s\n", lat); 
    printf("Longitude: %s\n", longitude); 
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

Upvote
Downvote
Loading...

Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E