Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    int length = 0;
    char token[7][10] = {0};
    int i = 0, j = 0;
    while (nmea[length] != '\0') {
        if (nmea[length] != ',') {
            token[i][j] = nmea[length];
            j++;
        }
        else {
            i++;
            j = 0;
        }
        length++;
    }
    printf("Time: %c%c:%c%c:%c%c\n",token[1][0],token[1][1],token[1][2],token[1][3],token[1][4],token[1][5]);
    printf("Latitude: %s %s\n",token[3],token[4]);
    printf("Longitude: %s %s",token[5],token[6]);
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach

 

 

 

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Input

$GPRMC,123519,A,4807.038,N,01131.000,E

Expected Output

Time: 12:35:19 Latitude: 4807.038 N Longitude: 01131.000 E