Parse GPS String for Time and Coordinates

Code

#include <stdio.h>
#include <string.h>

void parse_gprmc(char *nmea) {
    // Your logic here
    int i = 0;
    int count = 0, lcount = 0; 
    while(nmea[i] != '\0')
    {
        if(nmea[i] == ',')
        {
            count++;
        }
        else if(count == 1)
        {
            if(lcount == 0)
                printf("Time: ");
            
            printf("%d", nmea[i]%48);
                     
            lcount++;

            if((lcount % 2 == 0))
                if(lcount == 6)
                {
                    printf("\n");
                    lcount = 0;
                }
                else
                    printf(":");
        }
        else if(count == 3)
        {
            if(lcount == 0)
                printf("Latitude: ");
            
            if(nmea[i] != '.')
                printf("%d", nmea[i]%48);
            else
                printf("%c", nmea[i]);
                     
            lcount++;
        }
        else if(count == 4)
        {
            printf(" %C", nmea[i]);
            printf("\n");
            lcount = 0;
        }
        else if(count == 5)
        {
            if(lcount == 0)
                printf("Longitude: ");
            
            if(nmea[i] != '.')
                printf("%d", nmea[i]%48);
            else
                printf("%c", nmea[i]);
                     
            lcount++;
        }
        else if(count == 6)
        {
            printf(" %C", nmea[i]);
        }
        i++;
    }
}

int main() {
    char nmea[100];
    fgets(nmea, sizeof(nmea), stdin);
    parse_gprmc(nmea);
    return 0;
}

Solving Approach